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ABC is a triangle in which ∠A=90°. Let P be any point on side AC. If BC=10 cm, AC = 8cm and BP=9 cm, then AP=

- 3√3 cm
- 2√5
- 2√3 cm
- 3√5 cm

UncategorisedNo Comments

ABC is a triangle in which ∠A=90°. Let P be any point on side AC. If BC=10 cm, AC = 8cm and BP=9 cm, then AP=

- 3√3 cm
- 2√5
- 2√3 cm
- 3√5 cm

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