
The vectors (x1, y1) and (x2, y2) of V2 (F) are linearly dependent if x1y2x2y1= (a) x1y1 (b) x2y2 (c) …
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Express the vector α =(1, 2, 5) as a linear combination of e1 =(1, 1, 1), e2 = (1, 2, …
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In the polynomial ring Z2 [x], 91+x0³= (a) 1+x+x3 (b) 1+x+x2+x3 (c) 1+x2+x3 (d) x+x2+x3
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(a) 1,2 (b) 2, 3 (c) 0,2 (d) 0, 4
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(a) x is nilpotent (b) x is an idempotent (c) x is a zero divisor (d) none
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(a) 1+U (b) 1 (c) 0+U (d) 1+R
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Number of zero divisiors in a ring (Z12, +, .) is (a) 5 (b) 6 (c) 7 (d) 0
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(a) {0}, {i} (b) {0}, {1} (c) {i}, {1} (d) None
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(a) 1, 1 (b) I, i (c) 0, 1 (d) 1, i
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(a) 3 (b) 4 (c) 0 (d) 6
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(a) 0 (b) 2 (c) 3 (d) 4
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(a) 0 (b) 1 (c) 2 (d) ¥
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The idempotent elements of the ring(Z6 +, .) are (a) 1, 2 (c) 2, 3 (c) 3, 4 (d) 3, …
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If f=(2 3 4 1) is a permutation of degree 5 then f1= (a) (1 2 3 4) (b) (1 …
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(a) 6 (b) 8 (c) 9 (d) 7
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(a) 0 (b) 1 (c) n (d) ≈
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(a) 2 (b) 8 (c) 5 (d) 14
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Solution of x+5=3 in Z8 is (a) x=2 (b) x=8 (c) x=8 (d) x=1
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The generators of the cyclic group G=({0, 1, 0, 2, 3, 4, 5}, +6) are (a) 1, 2 (b) 1, …
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(a) H1 (b) H2 (c) H2 (d) H
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