Find Out the Angle ∠RQP, If
ABC is a cyclic triangle and the bisectors of ∠BAC, ∠ABC and ∠BAC meet the circle at P, Q and R respectively. Then the angle ∠RQP is:
- 90o – A/2
- 90o +B/2
- 90o –B/2
- 90o C/2
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Answer: (3) 90o –B/2
Explanation:-
In the figure-
∠RQP = 180 – 2 Y
= 90 – Y
= 90 – B/2 (Y = B/2)
Then the angle ∠RQP is 90 – B/2.
Hence, the answer is (3) 90o –B/2.
