# A hemispherical bowl has internal radius of 6 cm. The internal surface area would be:

(take π=3.14)

- 226.08 cm
^{2 } - 225 cm
^{2} - 400 cm
^{2 } - 298.75 cm
^{2}

**Answer: (1) 226.08 cm²
**

**Explanation:-
**The radius of the hemispherical bowl = 6 cm

**Formula:-**

The surface area of hemispherical bowl = 2 π r²

Then, the surface area of hemispherical bowl = 2 x 3.14 x 6 x 6

= 226.08 cm²

Hence, the answer is (1) 226.08 cm².