Find Out the Area Triangle of ABC, If
If two medians BE and CF of a triangle ABC, intersect each other at G and If BG = CG, ÐBGC =60o, BC =8cm, then area of the triangle ABC is:
- 48 cm2
- 64√3 cm2
- 96 √3 cm2
- 48 √3 cm2
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Answer : (4) 48 √3 cm2
Explanation:-
In the figure –
Three triangles are equal
Then, TriagleBCG = triangle ACG = triangle ABG
In triangle BCG,
GC = GB
Then, Angle GCB = Angle GBC
Then, triangle BCG is a equilateral triangle.
Then, the area of equilateral triangle BCG = 64 sqrt.3/4
= 16 sqrt.3
Then, the area of triangle ABC = 3 x 16 sqrt.3
= 48 sqrt.3
Hence, the answer is (4)48 √3 cm2
