# Find the distance between (7, 3) and (4, -1)

(a) 5 unit

(b) 3 unit

(c) 2 unit

(d) 6 unit

**Answer: (a) 5 unit **

**Solution:-**

**Formula of distance between two points= sqrt.{(x1- x2)^2 + (y1 – y2)^2}**

Then, the distance between (7, 3) and (4, -1).

= sqrt.{(7 – 4)^2 + (3 + 1)^2)}

= sqrt.{(3)^2 + (4)^2}

= sqrt.(9 + 16)

= sqrt.(25)

= 5 unit.

So, the distance between (7, 3) and (4, -1).

Hence, the correct answer is option (a) 5 unit.