Find The The Value of (v-e+f) ? If
If the number of vertices, edges and faces of a rectangular parallelepiped are denoted by v, e and f respectively, the value of (v-e+f) is:
- 2
- 0
- 1
- 4
Answer: (1) 2
Explanation:-
The number of vertices in rectangular parallelogram(v) = 8,
The number of edges rectangular parallelogram(e) = 12,
The number of faces rectangular parallelogram (f) = 6
Then, the value of v – e + f = 8 – 12 + 6
= 14 -12
= 2
Hence, the answer is (1) 2.
