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    In the polynomial ring Z2 [x], 91+x0³=

    In the polynomial ring Z2 [x], 91+x0³=
    (a) 1+x+x3
    (b) 1+x+x2+x3
    (c) 1+x2+x3
    (d) x+x2+x3

    Asked by Anurag Mishra on 28th May 2016 in Maths.
    0 Answers