Find the Least Number in Separately

Find the least number which divide separately by 15, 20, 36 and 48 leaves 3 as remainder in each case

  1. 183
  2. 243
  3. 483
  4. 723
Harsh Vardhan Professor Asked on 14th July 2015 in Maths.
Add Comment
  • 1 Answer(s)

    Answer: (4) 723
    Explanation:-
    The L C M of 15, 20, 36 and 48.
    Factors of 15 = 3 x 5
    Factors of 20 = 2 x 2 x 5
    Factors of 36 = 2 x 2 x 3 x 3
    Factors of 48 = 2 x 2 x 2 x 2 x 3
    The L C M = 2 x 2 x 2 x 2 x 3 x 3 x 5 = 720
    Remainder = 3
    Then, the least number = 720 + 3 = 723.
    Hence, the answer is (4) 723.

    Anurag Mishra Professor Answered on 14th July 2015.
    Add Comment

    Your Answer

    By posting your answer, you agree to the privacy policy and terms of service.