# If number 62532915a is completely divisible by 6 :

If number 62532915a is completely divisible by 6, then the largest digit at the place of ‘a’ will be

- 5
- 6
- 8
- 9

**Answer: (2) 6**

**Divisibility of 6 => ** If the number of 6 divisible 2 and 3 that number divisible by 6.**Divisibility of 2 **=>If the unit digit of the number if zero or even number that number divisible by 2.**Divisibility of 3** => If the sum of the digit of the number is divisible by 3 that number divisible by 3.

Then, the sum of the digit of the number 62532915 a = 6 + 2 + 5 + 3 + 2 + 9 + 1 + 5 + a

= 33 + a

If we put a = 6 which is a even number,the number surely divisible by 2.

And sum = 33 + 6 = 39 which is divisible 3.

Then, the largest digit at the place of ‘a’ will be 6.

Hence, the answer is (2) 6.