If sin θ=a/b, then the value of secθ – cos θ is (where 0º<θ<90º) :


  1. b²/a(√b²-a²)
  2. √(b²+ a²)/ √(b²- a²)
  3. a²/b√(b²-a²)
  4. a/b√(b²-a²)
Anurag Mishra Professor Asked on 27th December 2015 in Maths.
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  • 1 Answer(s)

    Answer: (3) a^2/b sqrt.(b^2 – a^2)

    Anurag Mishra Professor Answered on 30th December 2015.
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