# What will be the size of AP? If BC=10 cm, AC=8 cm

ABC is a triangle in which ∠A=90°. Let P be any point on side AC. If BC=10 cm, AC = 8cm and BP=9 cm, then AP=

- 3√3 cm
- 2√5
- 2√3 cm
- 3√5 cm

**Answer: (4) 3 √5**

**Explanation:-
**In triangle ABC,

In right angle triangle ABC,

AB² = √(BC² – CA²)

= √(10² – 8²)

=√(100 – 64)

AB² = √36

Square root on both side,

AB = 6 cm

Again in right triangle ABP,

AP² = √(BP² – AB²)

= √(9² – 6²)

= √(81 – 36)

AP² = √45

Square root on both side,

AP = 3 √5

Hence, the answer is (4) 3 √5.