# The Total Surface area of a Regular Triangular Pyramid with Each Edges of Length 1 cm is:

Answered

- sqrt. 3 sq. cm
- (4/3) sqrt. 3
- 4 sq. cm
- 4 sqrt. 3 sq. cm

**Warning**: Illegal string offset 'alt_text' in

**/srv/users/serverpilot/apps/edupil/public/wp-content/themes/edupil155/includes/theme.php**on line

**742**

**Warning**: Illegal string offset 'description' in

**/srv/users/serverpilot/apps/edupil/public/wp-content/themes/edupil155/includes/theme.php**on line

**743**

Best answer

**Warning**: Illegal string offset 'alt_text' in

**/srv/users/serverpilot/apps/edupil/public/wp-content/themes/edupil155/includes/theme.php**on line

**742**

**Warning**: Illegal string offset 'description' in

**/srv/users/serverpilot/apps/edupil/public/wp-content/themes/edupil155/includes/theme.php**on line

**743**

**Answer : (1). sqrt. 3 sq. cm**

In the above figure , we see that a regular triangular pyramid is made up of four equilateral triangles.

the equilateral triangle having each side = 1cm

so, total surface area of the above pyramid = **4 * area of one equilateral triangle.**** Total surface area of pyramid = 4 * 1 * sqrt.(3) / 4**** Total surface area of pyramid = sqrt.(3) * 4 / 4**** Total surface area of pyramid = sqrt.(3) sq. cm**