Find The Value of The Following Term ?
The value of sin222o + sin268o + cot230o is:
- 5/4
- 4
- 3/ 4
- 3
Answer: (2) 4
Explanation:-
Sin2220 + sin2680 + cot2300
= sin2220 + sin2 (90 – 22)o + cot230o
= sin222o + cos222o + cot230o [sin(90 – A) = cos A]
= 1 + cot230o [sin2A + cos2A = 1]
= 1 + (sqrt.3)2 (cot30o = sqrt.3)
= 1 + 3
= 4
Hence, the answer is (2) 4.