# Find The Value of The Following Term ?

The value of sin^{2}22^{o} + sin^{2}68^{o} + cot^{2}30^{o} is:

- 5/4
- 4
- 3/ 4
- 3

**Answer: (2) 4**

**Explanation:-
**

Sin^{2}22^{0} + sin^{2}68^{0} + cot^{2}30^{0}

= sin^{2}22^{0} + sin^{2} (90 – 22)^{o} + cot^{2}30^{o}

= sin^{2}22^{o} + cos^{2}22^{o} + cot^{2}30^{o} [sin(90 – A) = cos A]

= 1 + cot^{2}30^{o} [sin^{2}A + cos^{2}A = 1]

= 1 + (sqrt.3)^{2} (cot30^{o} = sqrt.3)

= 1 + 3

= 4

Hence, the answer is (2) 4.