# Then the average of such m + n numbers is

If the average of m numbers is n^{2} and that of n numbers is m^{2}, then the average of such m + n numbers is

(a) mn

(b) m + n

(c) m/n

(d) (m + n)/2

**Answer: (a) m n**

**Solution:-**

The average of m numbers = n^{2}

Therefore, the sum of m numbers = m x n^{2}

The average of n numbers = m^{2}

Therefore, the sum of n numbers = n x m^{2}

Total sum of m and n numbers = (m x n^{2} + n x m^{2})

= m n (n + m)

Then, the total average of m and n numbers = m n (n + m)/(n + m)

= m n

Hence, the correct answer is option (a) m n.