# Two trains are moving in the same direction at 65 kmph and 45 kmph

Two trains are moving in the same direction at 65 kmph and 45 kmph. The faster train crosses a man in slower train 18 seconds. The length of the first train is:

(a) 120 m

(b) 180 m

(c) 100 m

(d) 145 m

**Answer: (c) 100 m**

**Solution:-**

Let the length of both trains be X m and Y m.

Total distance covered by the faster train = (X + Y) m

Relative speed = 65 – 45 = 20 km/hr

= 20 x 5/18

= 100/18 m/sec

= 50/9 m/sec

Distance covered in 18 sec = 50 x 18/9

= 100 m

Then, the length of the first train is 100 m.

Hence, the correct answer is option (c) 100.